3.593 \(\int \frac{x^m}{\sqrt{a+b x^3}} \, dx\)

Optimal. Leaf size=52 \[ \frac{x^{m+1} \sqrt{a+b x^3} \, _2F_1\left (1,\frac{1}{6} (2 m+5);\frac{m+4}{3};-\frac{b x^3}{a}\right )}{a (m+1)} \]

[Out]

(x^(1 + m)*Sqrt[a + b*x^3]*Hypergeometric2F1[1, (5 + 2*m)/6, (4 + m)/3, -((b*x^3)/a)])/(a*(1 + m))

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Rubi [A]  time = 0.0180777, antiderivative size = 63, normalized size of antiderivative = 1.21, number of steps used = 2, number of rules used = 2, integrand size = 15, \(\frac{\text{number of rules}}{\text{integrand size}}\) = 0.133, Rules used = {365, 364} \[ \frac{x^{m+1} \sqrt{\frac{b x^3}{a}+1} \, _2F_1\left (\frac{1}{2},\frac{m+1}{3};\frac{m+4}{3};-\frac{b x^3}{a}\right )}{(m+1) \sqrt{a+b x^3}} \]

Antiderivative was successfully verified.

[In]

Int[x^m/Sqrt[a + b*x^3],x]

[Out]

(x^(1 + m)*Sqrt[1 + (b*x^3)/a]*Hypergeometric2F1[1/2, (1 + m)/3, (4 + m)/3, -((b*x^3)/a)])/((1 + m)*Sqrt[a + b
*x^3])

Rule 365

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Dist[(a^IntPart[p]*(a + b*x^n)^FracPart[p])
/(1 + (b*x^n)/a)^FracPart[p], Int[(c*x)^m*(1 + (b*x^n)/a)^p, x], x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[
p, 0] &&  !(ILtQ[p, 0] || GtQ[a, 0])

Rule 364

Int[((c_.)*(x_))^(m_.)*((a_) + (b_.)*(x_)^(n_))^(p_), x_Symbol] :> Simp[(a^p*(c*x)^(m + 1)*Hypergeometric2F1[-
p, (m + 1)/n, (m + 1)/n + 1, -((b*x^n)/a)])/(c*(m + 1)), x] /; FreeQ[{a, b, c, m, n, p}, x] &&  !IGtQ[p, 0] &&
(ILtQ[p, 0] || GtQ[a, 0])

Rubi steps

\begin{align*} \int \frac{x^m}{\sqrt{a+b x^3}} \, dx &=\frac{\sqrt{1+\frac{b x^3}{a}} \int \frac{x^m}{\sqrt{1+\frac{b x^3}{a}}} \, dx}{\sqrt{a+b x^3}}\\ &=\frac{x^{1+m} \sqrt{1+\frac{b x^3}{a}} \, _2F_1\left (\frac{1}{2},\frac{1+m}{3};\frac{4+m}{3};-\frac{b x^3}{a}\right )}{(1+m) \sqrt{a+b x^3}}\\ \end{align*}

Mathematica [A]  time = 0.0173365, size = 65, normalized size = 1.25 \[ \frac{x^{m+1} \sqrt{\frac{b x^3}{a}+1} \, _2F_1\left (\frac{1}{2},\frac{m+1}{3};\frac{m+1}{3}+1;-\frac{b x^3}{a}\right )}{(m+1) \sqrt{a+b x^3}} \]

Antiderivative was successfully verified.

[In]

Integrate[x^m/Sqrt[a + b*x^3],x]

[Out]

(x^(1 + m)*Sqrt[1 + (b*x^3)/a]*Hypergeometric2F1[1/2, (1 + m)/3, 1 + (1 + m)/3, -((b*x^3)/a)])/((1 + m)*Sqrt[a
+ b*x^3])

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Maple [F]  time = 0.026, size = 0, normalized size = 0. \begin{align*} \int{{x}^{m}{\frac{1}{\sqrt{b{x}^{3}+a}}}}\, dx \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(x^m/(b*x^3+a)^(1/2),x)

[Out]

int(x^m/(b*x^3+a)^(1/2),x)

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Maxima [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{m}}{\sqrt{b x^{3} + a}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(b*x^3+a)^(1/2),x, algorithm="maxima")

[Out]

integrate(x^m/sqrt(b*x^3 + a), x)

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Fricas [F]  time = 0., size = 0, normalized size = 0. \begin{align*}{\rm integral}\left (\frac{x^{m}}{\sqrt{b x^{3} + a}}, x\right ) \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(b*x^3+a)^(1/2),x, algorithm="fricas")

[Out]

integral(x^m/sqrt(b*x^3 + a), x)

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Sympy [C]  time = 1.26673, size = 53, normalized size = 1.02 \begin{align*} \frac{x x^{m} \Gamma \left (\frac{m}{3} + \frac{1}{3}\right ){{}_{2}F_{1}\left (\begin{matrix} \frac{1}{2}, \frac{m}{3} + \frac{1}{3} \\ \frac{m}{3} + \frac{4}{3} \end{matrix}\middle |{\frac{b x^{3} e^{i \pi }}{a}} \right )}}{3 \sqrt{a} \Gamma \left (\frac{m}{3} + \frac{4}{3}\right )} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x**m/(b*x**3+a)**(1/2),x)

[Out]

x*x**m*gamma(m/3 + 1/3)*hyper((1/2, m/3 + 1/3), (m/3 + 4/3,), b*x**3*exp_polar(I*pi)/a)/(3*sqrt(a)*gamma(m/3 +
4/3))

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Giac [F]  time = 0., size = 0, normalized size = 0. \begin{align*} \int \frac{x^{m}}{\sqrt{b x^{3} + a}}\,{d x} \end{align*}

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(x^m/(b*x^3+a)^(1/2),x, algorithm="giac")

[Out]

integrate(x^m/sqrt(b*x^3 + a), x)